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Daryl
Posts: 3601
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A random late at night thought of mine was -
If a hollow core starship was transparent, travelling at 0.8 C, a kilometre long, and some one shone a torch (flash light) from the back to an observer at the front, what would be seen? My take is that the observer in the ship would see normal light travelling at C; while an external observer would also see light travelling at C, but it would be frequency shifted. |
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tlb
Posts: 4776
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Exactly, light is always seen to travel at c; it is only the frequency that changed based on whether you are stationary compared to the source (as when both are on the ship, so wavelength the same) or moving compared to the source (the external observer, so wavelength longer or shorter). |
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Theemile
Posts: 5367
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Light always travels at C In a Vacuum. It travels slower in other media (due to interactions with the media). ******
RFC said "refitting a Beowulfan SD to Manticoran standards would be just as difficult as refitting a standard SLN SD to those standards. In other words, it would be cheaper and faster to build new ships." |
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tlb
Posts: 4776
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Of course, but discussions of relativity are usually limited to space (except for Cherenkov radiation). |
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ThinksMarkedly
Posts: 4664
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That's practically exactly the example that Einstein himself used when describing Special Relativity conditions, except he used a train instead of a starship. Later, when describing the Principle of Equivalence, he used a lift (elevator) instead of a starship under thrust. He was NOT a good sci-fi writer. |
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cthia
Posts: 14951
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Revisiting this exchange.
Indeed, but I am considering a missile that has a turbo mode that kicks in right before its final run which quickly accelerates the missile from .8C to damn near light speed. Thousands of missiles accelerating to just under the speed of light at those ranges will be unavoidable once they commit.
You answered the question yourself downstream. I knew you'd come around. Namely ...
Not only that, but time slows as C is approached. At what point would the observer observe the missiles' approach (speed) to suddenly cease? I did some related work with the equations when I was researching the Schwarzschild radius of a black hole. The physics gets a little hinky at C. So I am uncertain that HV sensors will operate appropriately at such enormous accelerations, as is. Just like Peep point defense shut down at the first sign of blossoming images of Manty missile tracks. The sensors simply might not be up to the task of accurately reporting what they "see." Even if the sensors don't just hiccup. Son, your mother says I have to hang you. Personally I don't think this is a capital offense. But if I don't hang you, she's gonna hang me and frankly, I'm not the one in trouble. —cthia's father. Incident in ? Axiom of Common Sense |
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tlb
Posts: 4776
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What I think you are saying: As the missile's speed increases; its relativistic mass does also, becoming infinite at the speed of light. So at some point the Schwarzschild radius will expand to the point where the missile is in a black hole and so invisible to an outside observer. What I do not understand about what you are saying: I do not remember anything from college Physics classes that said as an object's speed increases, time will slow and so the object will appear to stop to an outside observer. As I remember it, the Lorentz-FitzGerald contraction acts on space and not on time. What I think is wrong: The "relativistic mass increase" is a way of expressing the kinetic energy of a moving particle and does NOT really signal an increase in gravitational attraction (but someone with a grounding in General Relativity needs to comment on that). This is shown by the formula reducing to the Newtonian formula for kinetic energy plus a constant at speeds which are small compared to that of light. Since the Schwarzschild radius is related to the gravitational pull of an object, a missile will not develop a black hole at high speeds. |
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Theemile
Posts: 5367
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INTERNALLY time will slow as you approach C, with time flowing "normally" externally. Called the Twins paradox, a young twin accelerated to near C will barely age, but will return to find an old twin waiting for him. OR vice versa, from the perspective of the object moving at C, the external time seems to speed up. ******
RFC said "refitting a Beowulfan SD to Manticoran standards would be just as difficult as refitting a standard SLN SD to those standards. In other words, it would be cheaper and faster to build new ships." |
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tlb
Posts: 4776
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Okay, I'm caught up and I should have picked up on that, since I had already mentioned the Twins Paradox. However that does not cause the external observer to think that the object had stopped moving, which was the main cause of my confusion. |
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ThinksMarkedly
Posts: 4664
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The problem is again that it must shut down the wedge to be a kinetic energy weapon. If it hits with the wedge on, then we know that wedge fratricide will kill the less powerful one, and that's the missile. So it will be ballistic at hit time. Regardless of velocity. So it may turn a wedge on in the last 5 seconds. Let's say it had 1 million gravities of acceleration. Ignoring relativity (which we shouldn't at this point), that adds 0.163c. If the missile was already at 0.81c, that would bring it up at 0.97 or 0.98c. However, the fact that it turned a wedge on made it an extremely bright FTL sensor target, from over 5 light-seconds away. That's more than enough time to fire one last round of CM, though it would take a few hits first to learn it's necessary to keep one at stand-by.
Never. It's a smooth curve, according to Relativity. The only singularity in the curve happens when the speed is exactly c.
So does Math when you start dividing by zero.
Fair enough, there could be limitations in both software and hardware to keep track of such powerful wedges and whose positions are changing way too fast. |
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